For a phase change H 2 O ( l ) underset0° C , 1 textbar leftharpoons H 2 O ( s )

Question

For a phase change H 2 O ( l ) underset0° C , 1 textbar leftharpoons H 2 O ( s ) (A) Δ G =0 (B) Δ S =0 (C) Δ H =0 (D) Δ U =0

Tardigrade Admin · Accepted Answer

H 2 O ( l ) underset0° C , 1 textbar leftharpoons H 2 O ( s ) for equilibrium at constant pressure and temperature. G = A + PV d G = d A + PdV + VdP At constant T and P we obtain ( partial G ) T , P =0 for infinitesimal change (Δ G ) T , P >0

Q. For a phase change
$H_{2} O (l) 0^{\circ} C, 1 bar ⇌ H_{2} O (s)$

$Δ G = 0$

$Δ S = 0$

$Δ H = 0$

$Δ U = 0$

$H_{2} O (l) 0^{\circ} C, 1 bar ⇌ H_{2} O (s)$
for equilibrium at constant pressure and temperature.
$G = A + P V$
$d G = d A + P d V + V d P$
At constant $T$ and $P$ we obtain
$(\partial G)_{T, P} = 0$
for infinitesimal change
$(Δ G)_{T, P} > 0$

Q. For a phase change H2​O(l)0∘C,1bar⇌​H2​O(s)

ΔG=0

ΔS=0

ΔH=0

ΔU=0