For a particle of a mass 100 gm, position and velocity at any instant are given as 10 hati+6 hatj cm and vecv=5 hati cm / s. Calculate the angular momentum about the point (1,1) cm.

Question

For a particle of a mass 100 gm, position and velocity at any instant are given as 10 hati+6 hatj cm and vecv=5 hati cm / s. Calculate the angular momentum about the point (1,1) cm. (A) 25 × 10-5(- hatk) kgm 2 s -1 (B) 30 × 10-5(- hatk) kgm 2 s -1 (C) 3 × 10-3(- hatk) kgm 2 s -1 (D) 25 × 10-4(- hatk) kgm 2 s -1

Tardigrade Admin · Accepted Answer

vecL =m( vecr × vecv)=(100/1000)[(9 hati+5 hatj/100)] × (5 hati/100) =25 × 10-5(- hatk) kgm 2 s -1

Q. For a particle of a mass $100 g m$ , position and velocity at any instant are given as $10 \hat{i} + 6 \hat{j} c m$ and $v = 5 \hat{i} c m / s$ . Calculate the angular momentum about the point $(1, 1) c m$ .

$25 \times 1 0^{- 5} (- \hat{k}) k g m^{2} s^{- 1}$

$30 \times 1 0^{- 5} (- \hat{k}) k g m^{2} s^{- 1}$

$3 \times 1 0^{- 3} (- \hat{k}) k g m^{2} s^{- 1}$

$25 \times 1 0^{- 4} (- \hat{k}) k g m^{2} s^{- 1}$

$L = m (r \times v) = \frac{100}{1000} [\frac{9 i ^ + 5 j ^}{100}] \times \frac{5 i ^}{100}$
$= 25 \times 1 0^{- 5} (- \hat{k}) k g m^{2} s^{- 1}$

Q. For a particle of a mass 100gm, position and velocity at any instant are given as 10i^+6j^​cm and v=5i^cm/s. Calculate the angular momentum about the point (1,1)cm.

25×10−5(−k^)kgm2s−1

30×10−5(−k^)kgm2s−1

3×10−3(−k^)kgm2s−1

25×10−4(−k^)kgm2s−1