Q.
For a gas CvR=0.4, where R is the universal gas constant and Cv
is the molar specific heat at constant volume. The gas is made up
of molecules which are
2240
192
NTA AbhyasNTA Abhyas 2020Thermodynamics
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Solution:
CvR=0.4⇒CvCp−Cv=0.4 cvcp−1=0.4 ∴CvCp=1.4⇒γ=1.4
As γ=1.4, the gas is diatomic in nature. Example, air molecules.