For a certain reaction the variation of the rate constant with temperature is given by the equation ln Kt= ln K0+(( ln 3/10)) t(t ≥ 0° C ) The value of the temperature coefficient of the reaction rate is therefore.

Question

For a certain reaction the variation of the rate constant with temperature is given by the equation ln Kt= ln K0+(( ln 3/10)) t(t ≥ 0° C ) The value of the temperature coefficient of the reaction rate is therefore. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

ln ((Kt/K0))=(t/10)( ln 3) ; when t=10 ; (Kt/K0)= temperature coefficient ∴ ln ( temperature coefficient )=( ln 3) × (10/10)= ln 3 or temperature coefficient =3.

Q. For a certain reaction the variation of the rate constant with temperature is given by the equation
$ln K_{t} = ln K_{0} + (\frac{l n 3}{10}) t (t \geq 0^{\circ} C)$
The value of the temperature coefficient of the reaction rate is therefore.

$ln (\frac{K _{t}}{K _{0}}) = \frac{t}{10} (ln 3);$ when $t = 10;$
$\frac{K _{t}}{K _{0}} =$ temperature coefficient
$∴ ln ($ temperature coefficient $) = (ln 3) \times \frac{10}{10} = ln 3$
or temperature coefficient $= 3$ .

Q. For a certain reaction the variation of the rate constant with temperature is given by the equation lnKt​=lnK0​+(10ln3​)t(t≥0∘C) The value of the temperature coefficient of the reaction rate is therefore.

ln(K0​Kt​​)=10t​(ln3); when t=10; K0​Kt​​= temperature coefficient ∴ln( temperature coefficient )=(ln3)×1010​=ln3 or temperature coefficient =3.

Q. For a certain reaction the variation of the rate constant with temperature is given by the equation
$ln K_{t} = ln K_{0} + (\frac{l n 3}{10}) t (t \geq 0^{\circ} C)$
The value of the temperature coefficient of the reaction rate is therefore.

$ln (\frac{K _{t}}{K _{0}}) = \frac{t}{10} (ln 3);$ when $t = 10;$
$\frac{K _{t}}{K _{0}} =$ temperature coefficient
$∴ ln ($ temperature coefficient $) = (ln 3) \times \frac{10}{10} = ln 3$
or temperature coefficient $= 3$ .