For a certain first order reaction 32 % of the reactant is left after 570 s. The rate constant of this reaction is . × 10-3 s -1. (Round off to the Nearest Integer). [Given: . log 10 2=0.301, ln 10=2.303]

Question

For a certain first order reaction 32 % of the reactant is left after 570 s. The rate constant of this reaction is . × 10-3 s -1. (Round off to the Nearest Integer). [Given: . log 10 2=0.301, ln 10=2.303] (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

For 1 text st order reaction, K =(2.303/ t ) ⋅ log ([ A 0]/[ A t ])=(2.303/570 sec ) ⋅ log ((100/32)) =1.999 × 10-3 sec -1 ≈ 2 × 10-3 sec -1

Q. For a certain first order reaction $32%$ of the reactant is left after $570 s$ . The rate constant of this reaction is _____. $\times 1 0^{- 3} s^{- 1}$ . (Round off to the Nearest Integer).
[Given : $lo g_{10} 2 = 0.301, ln 10 = 2.303]$

For $1^{st}$ order reaction,

$K = \frac{2.303}{t} \cdot lo g \frac{[ A _{0} ]}{[ A _{t} ]} = \frac{2.303}{570 sec} \cdot lo g (\frac{100}{32})$

$= 1.999 \times 1 0^{- 3} se c^{- 1} \approx 2 \times 1 0^{- 3} se c^{- 1}$

Q. For a certain first order reaction 32% of the reactant is left after 570s. The rate constant of this reaction is _____. ×10−3s−1. (Round off to the Nearest Integer). [Given : log10​2=0.301,ln10=2.303]

For 1st order reaction, K=t2.303​⋅log[At​][A0​]​=570sec2.303​⋅log(32100​) =1.999×10−3sec−1≈2×10−3sec−1

Q. For a certain first order reaction $32%$ of the reactant is left after $570 s$ . The rate constant of this reaction is _____. $\times 1 0^{- 3} s^{- 1}$ . (Round off to the Nearest Integer).
[Given : $lo g_{10} 2 = 0.301, ln 10 = 2.303]$

For $1^{st}$ order reaction,

$K = \frac{2.303}{t} \cdot lo g \frac{[ A _{0} ]}{[ A _{t} ]} = \frac{2.303}{570 sec} \cdot lo g (\frac{100}{32})$

$= 1.999 \times 1 0^{- 3} se c^{- 1} \approx 2 \times 1 0^{- 3} se c^{- 1}$