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Tardigrade
Question
Chemistry
Following graph shows variation of ionization potential (IP) with atomic number in second period ( Li - Ne ). Value of ionization potential (IP) of Na (11) will be
Q. Following graph shows variation of ionization potential (IP) with atomic number in second period (
L
i
−
N
e
)
. Value of ionization potential (IP) of
N
a
(
11
)
will be
313
153
Classification of Elements and Periodicity in Properties
Report Error
A
Above Ne
40%
B
Below Ne but above O
25%
C
Below Li
17%
D
Between N and O
19%
Solution:
(IP) of
N
a
(
11
)
<
(
I
P
)
of
L
i
(
3
)
