The given circuit can be drawn as shown below
Equivalent resistance of circuit, Req=R1+R3+R2R2R3=3+2+22×2=4Ω
Net current drawn from battery I=RV=48=2A
Now the current I2 I2=R2+R3IR3=2+22×2=1A
and potential drop across R2 VR2=I2R2=1×2=2V