Q.
Find the sum of all the integral solution(s) of the equation 3∣x∣=((3)∣x−2∣3)2.
189
98
Continuity and Differentiability
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Answer: 3
Solution:
3∣x∣=((3)∣x−2∣3)2⇒3∣x∣=3∣x−2∣9 ⇒3∣x∣=32−∣x−2∣⇒∣x∣=2−∣x−2∣ ⇒∣x∣+∣x−2∣=2 Case-I : x<0 −x−x+2=2⇒−2x=0⇒x=0(No solution) Case-II : 0≤x≤2 ⇒x−x+2=2 ⇒2=2 ∴x∈[0,2]
Case-III : x>2 x+x−2=2⇒2x=4⇒x=2 (no solution) ∴x∈[0,2] is the solution set of the given equation ∴ Sum of all integers =0+1+2=3.