Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
Find the mean deviation about the mean for the following data: 12, 3, 18, 17, 4, 9, 17, 19, 20, 15, 8, 17, 2, 3, 16, 11, 3, 1, 0, 5
Q. Find the mean deviation about the mean for the following data :
12
,
3
,
18
,
17
,
4
,
9
,
17
,
19
,
20
,
15
,
8
,
17
,
2
,
3
,
16
,
11
,
3
,
1
,
0
,
5
1756
196
Statistics
Report Error
A
8.2
19%
B
9.2
22%
C
6.2
51%
D
5.2
8%
Solution:
The mean
(
x
ˉ
)
of the given data is,
x
ˉ
=
20
1
i
=
1
∑
20
x
i
=
20
200
=
10
The values of the deviations from mean, i.e.,
∣
x
i
−
x
ˉ
∣
are
2
,
7
,
8
,
7
,
6
,
1
,
7
,
9
,
10
,
5
,
2
,
7
,
8
,
7
,
6
,
1
,
7
,
9
,
10
,
5
∴
i
=
1
∑
20
∣
x
i
−
x
ˉ
∣
=
124
and
M
.
D
.
(
x
ˉ
)
=
20
124
=
6.2