Find the heat required to make water of 30 ° C from 10 g of ice at 0.0 ° C. (Enthalpy of fusion of ice =333.55 J g -1, Cp of water =4.18 Jg -1 K -1 )

Question

Find the heat required to make water of 30 ° C from 10 g of ice at 0.0 ° C. (Enthalpy of fusion of ice =333.55 J g -1, Cp of water =4.18 Jg -1 K -1 ) (A) 4.0 kJ (B) 5.0 kJ (C) 3.59 kJ (D) 4.59 kJ

Tardigrade Admin · Accepted Answer

Given, Initial temperature =0° C Final temperature =30° C Thus, Δ T=30° C Mass of ice (m)=10 g Enthalpy of fusion (L)=333.5 Jg -1 Cp of water =4.18 Jg -1 K -1 ∵ Heat required (Q)=m L+m Cp Δ T =10 × 333.5+10 × 4.18 × 30 =3335.0+1254.00 =4589 J =4.59 kJ

Q. Find the heat required to make water of 30∘C from 10g of ice at 0.0∘C. (Enthalpy of fusion of ice =333.55Jg−1,Cp​ of water =4.18Jg−1K−1 )

4.0 kJ

5.0 kJ

3.59 kJ

4.59 kJ

Given, Initial temperature =0∘C Final temperature =30∘C Thus, ΔT=30∘C Mass of ice (m)=10g Enthalpy of fusion (L)=333.5Jg−1 Cp​ of water =4.18Jg−1K−1 ∵ Heat required (Q)=mL+mCp​ΔT =10×333.5+10×4.18×30 =3335.0+1254.00 =4589J =4.59kJ

Q. Find the heat required to make water of $30^{\circ} C$ from $10 g$ of ice at $0.0^{\circ} C$ . (Enthalpy of fusion of ice $= 333.55 J g^{- 1}, C_{p}$ of water $= 4.18 J g^{- 1} K^{- 1}$ )