Find the compound interest on ₹ 40,000 at 12 % per annum for a period of 2 years. (in ₹)

Question

Find the compound interest on ₹ 40,000 at 12 % per annum for a period of 2 years. (in ₹) (A) 10,176 (B) 8000 (C) 9176 (D) 10,000

Tardigrade Admin · Accepted Answer

P =â¹ 40,000, R=12 %, n=2 . CI =P[(1+(R/100))n-1] =P[(1+(12/100))2-1] =40,000[((28/25))2-1] =40,000[(282-252/(25)2)] =40,000 ((28+25)(28-25)/25 × 25) =64 × 53 × 3=â¹ 10,176 .

Q. Find the compound interest on $₹40, 000$ at $12%$ per annum for a period of 2 years. (in ₹)

10,176

8000

9176

10,000

$P = ₹40, 000, R = 12%, n = 2.$
$C I = P [(1 + \frac{R}{100})^{n} - 1]$
$= P [(1 + \frac{12}{100})^{2} - 1]$
$= 40, 000 [(\frac{28}{25})^{2} - 1]$
$= 40, 000 [\frac{2 8 ^{2} - 2 5 ^{2}}{( 25 ) ^{2}}]$
$= 40, 000 \frac{( 28 + 25 ) ( 28 - 25 )}{25 \times 25}$
$= 64 \times 53 \times 3 = ₹10, 176.$

Q. Find the compound interest on ₹40,000 at 12% per annum for a period of 2 years. (in ₹)