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Tardigrade
Question
Mathematics
Find the area of the triangle whose vertices are (-2,6), (3,-6) and (1,5).
Q. Find the area of the triangle whose vertices are
(
−
2
,
6
)
,
(
3
,
−
6
)
and
(
1
,
5
)
.
6305
196
Determinants
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A
30 sq. units
16%
B
35 sq. units
23%
C
40 sq. units
19%
D
15.5 sq. units
42%
Solution:
Let
Δ
be the area of the triangle then,
Δ
=
2
1
∣
∣
−
2
3
1
6
−
6
5
1
1
1
∣
∣
Applying
R
1
→
R
1
−
R
2
and
R
2
−
R
3
, we get
Δ
=
2
1
∣
∣
−
5
2
1
12
−
11
5
0
0
1
∣
∣
Expanding along
C
3
, we get
Δ
=
2
1
∣
55
−
24
∣
=
15.5
sq. units