Question

Find out the compounds that will disproportionate in their aqueous solution.

$\left(I\right)Cl{O}_4^{-}\stackrel{+0.36V}{\to }Cl{O}_3^{-}\stackrel{+0.33V}{\to }Cl{O}_2\stackrel{+0.66V}{\to }OC{l}^{-}\stackrel{+0.40V}{\to }\frac{1}{2}C{l}_2\stackrel{+1.36V}{\to }C{l}^{-}$

$\left(II\right)Mn{O}_4^{-}\stackrel{+0.56V}{\to }Mn{O}_4^{2-}\stackrel{+2.22V}{\to }Mn{O}_2\stackrel{+0.95V}{\to }M{n}^{3+}\stackrel{+1.55V}{\to }M{n}^{2+}\stackrel{-0.19V}{\to }Mn$

(I)	(II)
$Cl{O}_2,C{l}_2$	$Mn{O}_4^{2-},M{n}^{3+}$
$Cl{O}_3^{-},OC{l}^{-}$	$Mn{O}_2,M{n}^{2+}$
$OC{l}^{-}$ only	$Mn{O}_2,M{n}^{2+}$
$Cl{O}_3^{-}$ only	$Mn{O}_2$ only

• A. A
• B. B
• C. C
• D. D

Answer 1

Answer: (A)

If the reaction sequence is written in reduction order then if right side reduction potential is higher than left side reduction potential then that compound will disproportionate.