Figure shows the variation of a force F acting on a particle along x-axis. If the particle begins at rest at x=0, what is the particle's coordinate when it again has zero speed?

Question

Figure shows the variation of a force F acting on a particle along x-axis. If the particle begins at rest at x=0, what is the particle's coordinate when it again has zero speed? (A) x=3 (B) x=6 (C) x=5 (D) x=7

Tardigrade Admin · Accepted Answer

Using work energy thorem WF=Δ K ∫ F d x=Δ K Given that Δ K=0 ⇒ ∫ F d x=0 (Area under F-x curve ) Positive area = Negative area So at x=6 Total area =0

Q. Figure shows the variation of a force $F$ acting on a particle along $x$ -axis. If the particle begins at rest at $x = 0$ , what is the particle's coordinate when it again has zero speed?

x=3

x=6

x=5

x=7

Using work energy thorem
$W_{F} = Δ K$
$\int F d x = Δ K$
Given that $Δ K = 0$
$\Rightarrow \int F d x = 0$ (Area under $F - x$ curve $)$
Positive area = Negative area
So at $x = 6$ Total area $= 0$

Q. Figure shows the variation of a force F acting on a particle along x-axis. If the particle begins at rest at x=0, what is the particle's coordinate when it again has zero speed?

x=3

x=6

x=5

x=7

Using work energy thorem WF​=ΔK ∫Fdx=ΔK Given that ΔK=0 ⇒∫Fdx=0 (Area under F−x curve ) Positive area = Negative area So at x=6 Total area =0

Q. Figure shows the variation of a force $F$ acting on a particle along $x$ -axis. If the particle begins at rest at $x = 0$ , what is the particle's coordinate when it again has zero speed?

Using work energy thorem
$W_{F} = Δ K$
$\int F d x = Δ K$
Given that $Δ K = 0$
$\Rightarrow \int F d x = 0$ (Area under $F - x$ curve $)$
Positive area = Negative area
So at $x = 6$ Total area $= 0$