Figure shows the strain-stress curve for a given material. The Young’s modulus for the material is

Question

Figure shows the strain-stress curve for a given material. The Young’s modulus for the material is (A) 5 × 109 Nm -2 (B) 5 × 1010 Nm -2 (C) 7.5 × 109 Nm -2 (D) 7.5 × 1010 Nm -2

Tardigrade Admin · Accepted Answer

For a stress of 150 × 106 Nm -2, the strain is 0.002 Hence Y=(150 × 106 Nm -2/0.002) =7.5 × 1010 Nm -2

Q. Figure shows the strain-stress curve for a given material. The Young’s modulus for the material is

$5 \times 1 0^{9} N m^{- 2}$

$5 \times 1 0^{10} N m^{- 2}$

$7.5 \times 1 0^{9} N m^{- 2}$

$7.5 \times 1 0^{10} N m^{- 2}$

For a stress of $150 \times 1 0^{6} N m^{- 2},$ the strain is 0.002
Hence $Y = \frac{150 \times 1 0 ^{6} N m ^{- 2}}{0.002}$
$= 7.5 \times 1 0^{10} N m^{- 2}$

Q. Figure shows the strain-stress curve for a given material. The Young’s modulus for the material is

5×109Nm−2

5×1010Nm−2

7.5×109Nm−2

7.5×1010Nm−2

For a stress of 150×106Nm−2, the strain is 0.002 Hence Y=0.002150×106Nm−2​ =7.5×1010Nm−2

$5 \times 1 0^{9} N m^{- 2}$

$5 \times 1 0^{10} N m^{- 2}$

$7.5 \times 1 0^{9} N m^{- 2}$

$7.5 \times 1 0^{10} N m^{- 2}$

For a stress of $150 \times 1 0^{6} N m^{- 2},$ the strain is 0.002
Hence $Y = \frac{150 \times 1 0 ^{6} N m ^{- 2}}{0.002}$
$= 7.5 \times 1 0^{10} N m^{- 2}$