Figure shows the electric lines of force emerging from a charged body. The electric field at A and B are EA and EB, respectively. If the distance between A and B is r, then

Question

Figure shows the electric lines of force emerging from a charged body. The electric field at A and B are EA and EB, respectively. If the distance between A and B is r, then (A) EA > EB (B) EA < EB (C) EA=(EB/r) (D) EA=(EB/r2)

Tardigrade Admin · Accepted Answer

In non-uniform electric field, intensity is more where the lines are more dense.

Q. Figure shows the electric lines of force emerging from a charged body. The electric field at $A$ and $B$ are $E_{A}$ and $E_{B}$ , respectively. If the distance between $A$ and $B$ is $r$ , then

$E_{A} > E_{B}$

$E_{A} < E_{B}$

$E_{A} = \frac{E _{B}}{r}$

$E_{A} = \frac{E _{B}}{r ^{2}}$

In non-uniform electric field, intensity is more where the lines are more dense.

Q. Figure shows the electric lines of force emerging from a charged body. The electric field at A and B are EA​ and EB​, respectively. If the distance between A and B is r, then

EA​>EB​

EA​<EB​

EA​=rEB​​

EA​=r2EB​​

In non-uniform electric field, intensity is more where the lines are more dense.

Q. Figure shows the electric lines of force emerging from a charged body. The electric field at $A$ and $B$ are $E_{A}$ and $E_{B}$ , respectively. If the distance between $A$ and $B$ is $r$ , then

$E_{A} > E_{B}$

$E_{A} < E_{B}$

$E_{A} = \frac{E _{B}}{r}$

$E_{A} = \frac{E _{B}}{r ^{2}}$