Question

Figure shows the displacement-time graphs of two simple harmonic motions$I$ and $II$. From the graph it follows that

• A. curve$I$ has same frequency as that of curve $II$
• B. curve $I$ has frequency twice that of curve $II$
• C. curve $I$ has frequency half that of curve $II$
• D. curve $I$ has frequency four times that of curve $II$

Answer 1

Answer: (C)

From the graphs
For curve $I$,
Time period, $T_1=8s,$
Frequency, ${\upsilon }_1=\frac{1}{T_1}=\frac{1}{8}Hz$
For curve $II$,
Time period, $T_2=4s$,
Frequency, ${\upsilon }_2=\frac{1}{T_2}=\frac{1}{4}Hz$
Their corresponding ratio
$\frac{{\upsilon }_1}{{\upsilon }_2}=\frac{1}{2}$ or ${\upsilon }_1=\frac{1}{2}{\upsilon }_2$