Figure shows a concavo - convex lens μ2. What is the condition on the reflective indices so that the lens is diverging?

Question

(A) 2 μ3 < μ1+μ2 (B) 2 μ3 > μ1+μ2 (C) μ3 > 2(μ1-μ2) (D) text none of these

Tardigrade Admin · Accepted Answer

(μ2/V)-(μ1/-u0)=(μ2-μ1/-2 R) (μ3/ V f )-(μ2/ V )=(μ3-μ2/- R ) (μ3/ V f )+(μ1/u0)=(μ1-μ2/2 R )+(μ2-μ3/R) ∴ (μ1-μ2/2)<μ3-μ2 ⇒ μ1-μ2< 2 μ3-2 μ2 ⇒ μ1+μ2<2 μ3 <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/de06071016f3252425c2c54eb3bf629a-.png" />

Q. Figure shows a concavo - convex lens $μ_{2}$ . What is the condition on the reflective indices so that the lens is diverging?

$2 μ_{3} < μ_{1} + μ_{2}$

$2 μ_{3} > μ_{1} + μ_{2}$

$μ_{3} > 2 (μ_{1} - μ_{2})$

$none of these$

Q. Figure shows a concavo - convex lens μ2​. What is the condition on the reflective indices so that the lens is diverging?

2μ3​<μ1​+μ2​

2μ3​>μ1​+μ2​

μ3​>2(μ1​−μ2​)

none of these

Vμ2​​−−u0​μ1​​=−2Rμ2​−μ1​​ Vf​μ3​​−Vμ2​​=−Rμ3​−μ2​​ Vf​μ3​​+u0​μ1​​=2Rμ1​−μ2​​+Rμ2​−μ3​​ ∴2μ1​−μ2​​<μ3​−μ2​ ⇒μ1​−μ2​<2μ3​−2μ2​ ⇒μ1​+μ2​<2μ3​

Q. Figure shows a concavo - convex lens $μ_{2}$ . What is the condition on the reflective indices so that the lens is diverging?

$2 μ_{3} < μ_{1} + μ_{2}$

$2 μ_{3} > μ_{1} + μ_{2}$

$μ_{3} > 2 (μ_{1} - μ_{2})$

$none of these$