Figure represents an area A=0.5 m2 situated in a uniform magnetic field B=2.0 Wb/m2 and making an angle of 60° with respect to magnetic field. The value of magnetic flux through the area will be

Question

Figure represents an area A=0.5 m2 situated in a uniform magnetic field B=2.0 Wb/m2 and making an angle of 60° with respect to magnetic field. The value of magnetic flux through the area will be (A) 0.5 Wb (B)  √3 Wb  (C)  (3/2)Wb  (D) 2.0 Wb

Tardigrade Admin · Accepted Answer

As φ=B ⋅ A ⇒ φ=2 × 0.5 × cos 60° =2 × 0.5 × (1/2)=0.5 Wb

Q. Figure represents an area $A = 0.5 m^{2}$ situated in a uniform magnetic field $B = 2.0 Wb / m^{2}$ and making an angle of $60^{\circ}$ with respect to magnetic field. The value of magnetic flux through the area will be

0.5 Wb

$3 Wb$

$\frac{3}{2} Wb$

2.0 Wb

As $ϕ = B \cdot A$
$\Rightarrow ϕ = 2 \times 0.5 \times cos 6 0^{\circ}$
$= 2 \times 0.5 \times \frac{1}{2} = 0.5 Wb$

Q. Figure represents an area A=0.5m2 situated in a uniform magnetic field B=2.0Wb/m2 and making an angle of 60∘ with respect to magnetic field. The value of magnetic flux through the area will be

0.5 Wb

3​Wb

23​Wb

2.0 Wb

As ϕ=B⋅A ⇒ϕ=2×0.5×cos60∘ =2×0.5×21​=0.5Wb

Q. Figure represents an area $A = 0.5 m^{2}$ situated in a uniform magnetic field $B = 2.0 Wb / m^{2}$ and making an angle of $60^{\circ}$ with respect to magnetic field. The value of magnetic flux through the area will be

$3 Wb$

$\frac{3}{2} Wb$

As $ϕ = B \cdot A$
$\Rightarrow ϕ = 2 \times 0.5 \times cos 6 0^{\circ}$
$= 2 \times 0.5 \times \frac{1}{2} = 0.5 Wb$