Few electrons have following quantum numbers, (i) n=4, l=1 (ii) n=4, l=0 (iii) n=3, l=2 (iv) n=3, l=1 Arrange them in the order of increasing energy from lowest to highest.

Question

Few electrons have following quantum numbers, (i) n=4, l=1 (ii) n=4, l=0 (iii) n=3, l=2 (iv) n=3, l=1 Arrange them in the order of increasing energy from lowest to highest. (A) (iv)< (ii)< (iii)< (i) (B) (ii)< (iv)< (i)< (iii) (C) (i)< (iii)< (ii)< (iv) (D) (iii) < (i) < (iv) < (ii)

Tardigrade Admin · Accepted Answer

(i) n=4, l=1 ⇒ 4 p-orbital (ii) n=4, l=0 ⇒ 4 s-orbital (iii) n=3, l=2 ⇒ 3 d-orbital (iv) n=3, l=1 ⇒ 3 d-orbital According to Aufbau principle, energies of above mentioned orbitals are in the order of (iv) 3 p< (ii) 4 s< (iii) 3 d< (i) 4 p

Q. Few electrons have following quantum numbers, (i) n=4,l=1 (ii) n=4,l=0 (iii) n=3,l=2 (iv) n=3,l=1 Arrange them in the order of increasing energy from lowest to highest.

(iv)< (ii)< (iii)< (i)

(ii)< (iv)< (i)< (iii)

(i)< (iii)< (ii)< (iv)

(iii) < (i) < (iv) < (ii)

(i) n=4,l=1⇒4p-orbital (ii) n=4,l=0⇒4s-orbital (iii) n=3,l=2⇒3d-orbital (iv) n=3,l=1⇒3d-orbital According to Aufbau principle, energies of above mentioned orbitals are in the order of (iv)3p<(ii)4s<(iii)3d<(i)4p

Q. Few electrons have following quantum numbers,
(i) $n = 4, l = 1$
(ii) $n = 4, l = 0$
(iii) $n = 3, l = 2$
(iv) $n = 3, l = 1$
Arrange them in the order of increasing energy from lowest to highest.