Ferric ion forms a Prussian blue precipitate due to the formation of

Question

Ferric ion forms a Prussian blue precipitate due to the formation of (A) K4[Fe(CN)6] (B) K3[Fe(CN)6] (C) Fe(CNS)3 (D) Fe4[Fe(CN)6]3

Tardigrade Admin · Accepted Answer

Ferric ion forms a prussian blue precipitate due to the formation of

F e_{4} [F e (CN)_{6}]_{3}

. This complex is formed during the determine action of presence of nitrogen in the given sample. In this method, to portion of sodium fusion extract, freshly prepared ferrous sulphate,

F e S O_{4}

solution is added and warmed. Then about 2 to 3 drops of

F e C l_{3}

solution are added and acidified with conc. HCl. The appearance of a prussian blue colour indicate the presence of nitrogen.

F e S O_{4} + 2 N a O H ⟶ F e (O H)_{2} + N a_{2} S O_{4}

6 N a CN + F e (O H)_{2} ⟶ Sodium ferrocyanide N a_{4} [F e (CN)_{6}] + 2 N a O H

3 N a_{4} [F e (CN)_{6}] + 4 F e C l_{3} ⟶ Ferric ferrocyanide (prussian blue) F e_{4} [F e (CN)_{6}]_{3} + 12 N a Cl

Q. Ferric ion forms a Prussian blue precipitate due to the formation of

$K_{4} [F e (CN)_{6}]$

$K_{3} [F e (CN)_{6}]$

$F e (CNS)_{3}$

$F e_{4} [F e (CN)_{6}]_{3}$

Q. Ferric ion forms a Prussian blue precipitate due to the formation of

K4​[Fe(CN)6​]

K3​[Fe(CN)6​]

Fe(CNS)3​

Fe4​[Fe(CN)6​]3​

$K_{4} [F e (CN)_{6}]$

$K_{3} [F e (CN)_{6}]$

$F e (CNS)_{3}$

$F e_{4} [F e (CN)_{6}]_{3}$