Question

Ferric alum gives red colour with $N{H}_{4}SCN$ due to formation of

• A. $Al(SCN{)}_3$
• B. ${\left[Fe(SCN{)}_3\right]}^{-}$
• C. $Fe(SCN{)}_3$
• D. $[Fe(SCN){]}^{2+}$

Answer 1

Answer: (D)

$F{e}^{3+}+SC{N}^{-}\to [Fe(SCN){]}^{2+}$