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Tardigrade
Question
Chemistry
[ Fe II ( O 2)( CN )4 Cl ]4- is named as
Q.
[
F
e
II
(
O
2
)
(
CN
)
4
Cl
]
4
is named as
1516
202
Coordination Compounds
Report Error
A
chlorotetracyanodioxoferrate(II) ion
B
chlorotetracyanoperoxoferrate(II) ion
C
chlorotetracyanosuperoxoferrate(II) ion
D
chlorotetracyanooxoferrate(II) ion
Solution:
Option (C) is correct.
[
F
e
(
O
2
)
(
CN
)
4
Cl
]
4
−
is named as chlorotetracyanosuperoxoferrate (II) ion. In the complex iron is in
+
2
oxidation state, so
O
2
acts as superoxo having
−
1
oxidation state
(
O
2
−
)