Tardigrade
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Tardigrade
Question
Chemistry
[ Fe ( H 2 O )6]2+ and [ Fe ( CN )6]4- differ in
Q.
[
F
e
(
H
2
O
)
6
]
2
+
and
[
F
e
(
CN
)
6
]
4
−
differ in
2280
192
NTA Abhyas
NTA Abhyas 2020
Coordination Compounds
Report Error
A
geometry, magnetic moment
0%
B
geometry, hybridization
57%
C
magnetic moment, colour
43%
D
hybridisation, number of d-electrons
0%
Solution:
[
F
e
(
H
2
O
)
6
]
2
+
and
[
F
e
(
CN
)
6
]
4
−
differ in magnetic moment and colour.
F
e
2
+
in
[
F
e
(
H
2
O
)
6
]
2
+
Colour: Pale green
μ
=
4.9
B.M.; octahedral
F
e
2
+
in
[
F
e
(
CN
)
6
]
4
−
Colour: Yellow;
μ
=
0
; octahedral.