Excess of KI reacts with CuSO4 solution and then Na2S2O3 solution is added to it. Which of the statements is incorrect for this reaction?

Question

Excess of KI reacts with CuSO4 solution and then Na2S2O3 solution is added to it. Which of the statements is incorrect for this reaction? (A)  textC textu text2 textI text2 is formed (B)  textCu textI text2 is formed (C)  Na2S2O3 is oxidized (D) Evolved I2 is reduced

Tardigrade Admin · Accepted Answer

Copper sulphate reacts with K I to give cuprous iodide and iodine. 2 C u S O4+4 K I arrow C u2 I2+2 K2 S O4+I2 I2+2 N a2 S2 O3 arrow N a2 S4 O6+2 N a I In the second reaction oxidation number of I 2 changes from zero ( in I 2) to -1 (in NaI ). Thus, it is reduced. Oxidation number of S changes from +2(. in .Na 2 S 2 O 3) to 2.5(. in .Na 2 S 4 O 6). Thus, N a2 S2 O3 is oxidised.

Q. Excess of $K I$ reacts with $C u S O_{4}$ solution and then $N a_{2} S_{2} O_{3}$ solution is added to it. Which of the statements is incorrect for this reaction?

$C u_{2} I_{2}$ is formed

$Cu I_{2}$ is formed

$N a_{2} S_{2} O_{3}$ is oxidized

Evolved $I_{2}$ is reduced

Q. Excess of KI reacts with CuSO4​ solution and then Na2​S2​O3​ solution is added to it. Which of the statements is incorrect for this reaction?

Cu2​I2​ is formed

CuI2​ is formed

Na2​S2​O3​ is oxidized

Evolved I2​ is reduced

Q. Excess of $K I$ reacts with $C u S O_{4}$ solution and then $N a_{2} S_{2} O_{3}$ solution is added to it. Which of the statements is incorrect for this reaction?

$C u_{2} I_{2}$ is formed

$Cu I_{2}$ is formed

$N a_{2} S_{2} O_{3}$ is oxidized

Evolved $I_{2}$ is reduced