Ethylene glycol is used as an antifreeze in a cold climate Mass of ethylene glycol which should be added to 4 kg of water to prevent it from freezing at - 6°C will be (Kf for water = 1.86 K kg mol-1 and molar mass of ethylene glycol = 62 g mol-1)

Question

Ethylene glycol is used as an antifreeze in a cold climate Mass of ethylene glycol which should be added to 4 kg of water to prevent it from freezing at - 6°C will be (Kf for water = 1.86 K kg mol-1 and molar mass of ethylene glycol = 62 g mol-1) (A) 800 g (B) 204.30 g (C) 400.00 g (D) 304.60 g

Tardigrade Admin · Accepted Answer

Δ Tf = Freezing point of H2O - freezing point of ethylene glycol solution =0-(-6°)=6° Kf=1.86°K kg mol-1 w1 = Mass of ethylene glycol in grams w2 = Mass of solvent (H2O) in grams = 4000 g m1 = Molar mass of ethylene glycol =62 g mol-1 Δ Tf =(1000Kf w1/62×4000) w1=800 g

Q. Ethylene glycol is used as an antifreeze in a cold climate Mass of ethylene glycol which should be added to $4$ kg of water to prevent it from freezing at - $6^{\circ} C$ will be $(K_{f}$ for water $= 1.86 K k g m o l^{- 1}$ and molar mass of ethylene glycol $= 62 g m o l^{- 1})$

$800 g$

$204.30 g$

$400.00 g$

$304.60 g$

Q. Ethylene glycol is used as an antifreeze in a cold climate Mass of ethylene glycol which should be added to 4 kg of water to prevent it from freezing at - 6∘C will be (Kf​ for water =1.86Kkgmol−1 and molar mass of ethylene glycol =62gmol−1)

800g

204.30g

400.00g

304.60g

Q. Ethylene glycol is used as an antifreeze in a cold climate Mass of ethylene glycol which should be added to $4$ kg of water to prevent it from freezing at - $6^{\circ} C$ will be $(K_{f}$ for water $= 1.86 K k g m o l^{- 1}$ and molar mass of ethylene glycol $= 62 g m o l^{- 1})$

$800 g$

$204.30 g$

$400.00 g$

$304.60 g$