Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
Ethyl alcohol on,oxidation with K2Cr2O7 gives
Q. Ethyl alcohol on,oxidation with
K
2
C
r
2
O
7
gives
5003
244
Alcohols Phenols and Ethers
Report Error
A
Acetic acid
35%
B
Acetaldehyde
28%
C
Formaldehyde
18%
D
Formic acid
19%
Solution:
Ethyl alcohol on oxidation with
K
2
C
r
2
O
7
gives Acetic acid.
C
H
3
C
H
2
O
H
→
K
2
C
r
2
O
7
C
H
3
C
O
O
H