Tardigrade
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Tardigrade
Question
Chemistry
Ethyl alcohol is heated with conc. H2SO4. The product formed is
Q. Ethyl alcohol is heated with conc.
H
2
S
O
4
. The product formed is
1397
236
AMU
AMU 2006
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A
C
H
3
−
C
∣∣
O
−
O
C
2
H
5
B
C
2
H
6
C
C
2
H
4
D
C
2
H
2
Solution:
Ethyl alcohol on dehydration with conc.
H
2
S
O
4
at
17
0
∘
C
, gives ethylene.
C
H
3
C
H
2
O
H
17
0
∘
C
co
n
c
.
H
2
S
O
4
ethylene
C
H
2
=
C
H
2
+
H
2
O