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Tardigrade
Question
Chemistry
Equivalent weight of FeS 2 (mol. wt. =M ) in the following reaction is FeS 2+ O 2 arrow Fe 2 O 3+ SO 2
Q. Equivalent weight of
F
e
S
2
(mol. wt.
=
M
) in the following reaction is
F
e
S
2
+
O
2
→
F
e
2
O
3
+
S
O
2
2704
205
Redox Reactions
Report Error
A
M
/2
37%
B
M
/4
24%
C
M
/11
30%
D
M
/14
9%
Solution:
Calculate total change in oxidation number (O.N.) of one molecules of
F
e
S
2
F
e
S
2
=
F
e
2
+
+
2
S
−
F
e
2
+
→
F
e
3
+
(
in
2
1
F
e
2
O
3
)
,
Increase
=
1
2
S
−
→
2
S
O
2
+
4
,
Increase
=
10
Total Increase
=
11
∴
Equivalent wt. = Molecular weight
/11