Equivalent weight of Br 2 is 96 in the following disproportionation reaction: Br 2+ OH - arrow Br + H 2 O + X The oxidised product is: ( Br =80)

Question

Equivalent weight of Br 2 is 96 in the following disproportionation reaction: Br 2+ OH - arrow Br + H 2 O + X The oxidised product is: ( Br =80) (A) BrO - (B) BrO 2- (C) BrO 3- (D) BrO 4-

Tardigrade Admin · Accepted Answer

Eq. wt. in disproportionation reaction =( M / n text factor 1)+( M / n text factor 2) 96=(160/2)+(160/ n text factor 2) ⇒ 16=(160/ n text factor 2) n factor 2=10 which is possible only if the oxidised product is BrO 3-.

Q. Equivalent weight of $B r_{2}$ is 96 in the following disproportionation reaction:
$B r_{2} + O H^{-} \to B r + H_{2} O + X$
The oxidised product is: $(B r = 80)$

$B r O^{-}$

$B r O_{2}^{-}$

$B r O_{3}^{-}$

$B r O_{4}^{-}$

Eq. wt. in disproportionation reaction

$= \frac{M}{n factor _{1}} + \frac{M}{n factor _{2}}$

$96 = \frac{160}{2} + \frac{160}{n factor _{2}}$

$\Rightarrow 16 = \frac{160}{n factor _{2}}$

n factor $_{2} = 10$

which is possible only if the oxidised product is $B r O_{3}^{-}$ .

Q. Equivalent weight of Br2​ is 96 in the following disproportionation reaction: Br2​+OH−→Br+H2​O+X The oxidised product is: (Br=80)

BrO−

BrO2−​

BrO3−​

BrO4−​