Equimolar solutions of two non-electrolytes in the same solvent have:

Question

Equimolar solutions of two non-electrolytes in the same solvent have: (A) Same b.pt. but different f.pt. (B) Same f.pt. but different b.pt. (C) Same b.pt. and same f.pt. (D) Different b.pt. and different f.pt

Tardigrade Admin · Accepted Answer

Δ Tf=Kf × molality Δ Tb =Kb × molality Thus, Tf and Δ Tb for different non-electrolytes is same as Kf and Kb are constant

Q. Equimolar solutions of two non-electrolytes in the same solvent have:

Same b.pt. but different f.pt.

Same f.pt. but different b.pt.

Same b.pt. and same f.pt.

Different b.pt. and different f.pt

$Δ T_{f} = K_{f} \times$ molality
$Δ T_{b} = K_{b} \times$ molality
Thus, $T_{f}$ and $Δ T_{b}$ for different non-electrolytes is same as $K_{f}$ and $K_{b}$ are constant

Q. Equimolar solutions of two non-electrolytes in the same solvent have:

Same b.pt. but different f.pt.

Same f.pt. but different b.pt.

Same b.pt. and same f.pt.

Different b.pt. and different f.pt

ΔTf​=Kf​× molality ΔTb​=Kb​× molality Thus, Tf​ and ΔTb​ for different non-electrolytes is same as Kf​ and Kb​ are constant

$Δ T_{f} = K_{f} \times$ molality
$Δ T_{b} = K_{b} \times$ molality
Thus, $T_{f}$ and $Δ T_{b}$ for different non-electrolytes is same as $K_{f}$ and $K_{b}$ are constant