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Tardigrade
Question
Chemistry
Equimolar solutions of HF, HCOOH and HCN at 298 K have the values of Ka as 6.8 × 10-4, 1.8 × 10-4 and 4.8 × 10-9 respectively. What will be the order of their acidic strength?
Q. Equimolar solutions of
H
F
,
H
COO
H
and
H
CN
at
298
K
have the values of
K
a
as
6.8
×
1
0
−
4
,
1.8
×
1
0
−
4
and
4.8
×
1
0
−
9
respectively. What will be the order of their acidic strength?
2436
231
Equilibrium
Report Error
A
H
F
>
H
CN
>
H
COO
H
17%
B
H
F
>
H
COO
H
>
H
CN
67%
C
H
CN
>
H
F
>
H
COO
H
9%
D
H
COO
H
>
H
CN
>
H
F
7%
Solution:
Acidic strength
∝
K
a