Equilibrium constants K1 and K2 for the following equilibria NO(g)+(1/2)O2 leftharpoons NO2(g) and 2NO2(g) leftharpoons 2NO(g)+O2(g) are related as

Question

Equilibrium constants K1 and K2 for the following equilibria NO(g)+(1/2)O2 leftharpoons NO2(g) and 2NO2(g) leftharpoons 2NO(g)+O2(g) are related as (A)  K2=(1/K1)  (B)  K2=K12  (C)  K2=(K1/2)  (D)  K2=(1/=K12)

Tardigrade Admin · Accepted Answer

(i) NO(g)+(1/2)O2(g)NO2(g) So, K1=([NO2]/[NO][O2]1/2) ..(i) (ii) 2NO2(g)2NO+O2(g) So, K2=([NO]2[O2]/[NO2]2) ..(ii) From Eq. (i) K12=([NO2]2/[NO]2[O2]) or (1/K12)=([NO]2[O2]/[NO2]2) ..(iii) From Eqs. (i) and (iii) K2=(1/K12)

Q. Equilibrium constants $K_{1}$ and $K_{2}$
for the following equilibria
$NO (g) + \frac{1}{2} O_{2} ⇌ N O_{2} (g)$
and $2 N O_{2} (g) ⇌ 2 NO (g) + O_{2} (g)$
are related as

$K_{2} = \frac{1}{K _{1}}$

$K_{2} = K_{1}^{2}$

$K_{2} = \frac{K _{1}}{2}$

$K_{2} = \frac{1}{= K _{1} ^{2}}$

Q. Equilibrium constants K1​ and K2​ for the following equilibria NO(g)+21​O2​⇌NO2​(g) and 2NO2​(g)⇌2NO(g)+O2​(g) are related as

K2​=K1​1​

K2​=K1​2

K2​=2K1​​

K2​==K1​21​

(i) NO(g)+21​O2​(g)NO2​(g) So, K1​=[NO][O2​]1/2[NO2​]​ ..(i) (ii) 2NO2​(g)2NO+O2​(g) So, K2​=[NO2​]2[NO]2[O2​]​ ..(ii) From Eq. (i) K1​2=[NO]2[O2​][NO2​]2​ or K12​1​=[NO2​]2[NO]2[O2​]​ ..(iii) From Eqs. (i) and (iii) K2​=K12​1​

Q. Equilibrium constants $K_{1}$ and $K_{2}$
for the following equilibria
$NO (g) + \frac{1}{2} O_{2} ⇌ N O_{2} (g)$
and $2 N O_{2} (g) ⇌ 2 NO (g) + O_{2} (g)$
are related as

$K_{2} = \frac{1}{K _{1}}$

$K_{2} = K_{1}^{2}$

$K_{2} = \frac{K _{1}}{2}$

$K_{2} = \frac{1}{= K _{1} ^{2}}$