Equation of the hour hand at 4 O' clock is

Question

Equation of the hour hand at 4 O' clock is (A) x-√3y=0 (B) √3x-y=0 (C) x+√3y=0 (D) √3x+y=0

Tardigrade Admin · Accepted Answer

Since the hour, minute and second hand always pass through origin because one end of these hands is always at origin. Now at 4 O' clock, the hour hand makes

3 0^{°}

angle in fourth quadrant. So the equation of hour hand is

y = m x \Rightarrow y = - \frac{1}{3} x

\Rightarrow x + 3 y = 0

Q. Equation of the hour hand at 4 O' clock is

$x - 3 y = 0$

$3 x - y = 0$

$x + 3 y = 0$

$3 x + y = 0$

Since the hour, minute and second hand always pass through origin because one end of these hands is always at origin. Now at 4 O' clock, the hour hand makes $3 0^{°}$ angle in fourth quadrant. So the equation of hour hand is
$y = m x \Rightarrow y = - \frac{1}{3} x$
$\Rightarrow x + 3 y = 0$

Q. Equation of the hour hand at 4 O' clock is

x−3​y=0

3​x−y=0

x+3​y=0

3​x+y=0

Since the hour, minute and second hand always pass through origin because one end of these hands is always at origin. Now at 4 O' clock, the hour hand makes 30° angle in fourth quadrant. So the equation of hour hand is y=mx⇒y=−3​1​x ⇒x+3​y=0

$x - 3 y = 0$

$3 x - y = 0$

$x + 3 y = 0$

$3 x + y = 0$

Since the hour, minute and second hand always pass through origin because one end of these hands is always at origin. Now at 4 O' clock, the hour hand makes $3 0^{°}$ angle in fourth quadrant. So the equation of hour hand is
$y = m x \Rightarrow y = - \frac{1}{3} x$
$\Rightarrow x + 3 y = 0$