Equal weights of ethane and hydrogen are mixed in an empty container at 25°C. The The fraction of total pressure exerted by hydrogen is

Question

Equal weights of ethane and hydrogen are mixed in an empty container at 25°C. The The fraction of total pressure exerted by hydrogen is (A) 1: 2 (B) 1: 1 (C) 1: 16 (D) 15: 16

Tardigrade Admin · Accepted Answer

Given, equal weights of ethane and hydrogen are mixed in an empty container at

2 5^{\circ} C

Initial gram weight =

w g C_{2} H_{6} w g H_{2}

Number of moles

= \frac{w}{30} \frac{w}{2}

According to Henry's law,

\frac{p _{H_{2}}}{p _{total}} = χ_{H_{2}} = \frac{n _{H_{2}}}{n _{H_{2}} + n _{C_{2} H_{6}}} = \frac{\frac{w}{2}}{\frac{w}{2} + \frac{w}{30}}

\frac{p _{H_{2}}}{p _{total}} = \frac{\frac{w}{2}}{\frac{15 w + w}{30}} = \frac{w}{2} \times \frac{30}{16 w} = \frac{15}{16}

So, the fraction of total pressure exerted by hydrogen is

15 : 16

Q. Equal weights of ethane and hydrogen are mixed in an empty container at $2 5^{\circ} C$ . The The fraction of total pressure exerted by hydrogen is

1 : 2

1 : 1

1 : 16

15 : 16

Q. Equal weights of ethane and hydrogen are mixed in an empty container at 25∘C. The The fraction of total pressure exerted by hydrogen is

1 : 2

1 : 1

1 : 16

15 : 16

Q. Equal weights of ethane and hydrogen are mixed in an empty container at $2 5^{\circ} C$ . The The fraction of total pressure exerted by hydrogen is