Energy released when one atom of uranium undergoes nuclear fission according to the following reaction is (atomic mass of U= 235.060; n= 1.009; Ba = 143.881 and Kr= 89.947) about 92U235+0n1→ 56Ba144+36Kr90+20n1

Question

Energy released when one atom of uranium undergoes nuclear fission according to the following reaction is (atomic mass of U= 235.060; n= 1.009; Ba = 143.881 and Kr= 89.947) about 92U235+0n1→ 56Ba144+36Kr90+20n1  (A) 235 MeV (B) 208 MeV (C) 931.5 MeV (D)  5.33× 1023MeV

Tardigrade Admin · Accepted Answer

Mass defect, Δ m=Z mass of reactants - Sigma mass of products Δ m=235.060-(143.881+89.947+1.009) =0.223 Binding energy or the energy released =0.223× 931 MeV =207.6MeV =208 text MeV

Q. Energy released when one atom of uranium undergoes nuclear fission according to the following reaction is (atomic mass of U= 235.060; n= 1.009; Ba = 143.881 and Kr= 89.947) about $_{92} U^{235} +_{0} n^{1} \to_{56} B a^{144} +_{36} K r^{90} + 2_{0} n^{1}$

235 MeV

208 MeV

931.5 MeV

$5.33 \times 10^{23} M e V$

20.8 MeV

Mass defect, $Δ m = Z$ mass of reactants $- Σ$ mass of products $Δ m = 235.060 - (143.881 + 89.947 + 1.009)$
$= 0.223$
Binding energy or the energy released
$= 0.223 \times 931 M e V$
$= 207.6 M e V$
$= 208 M e V$

Q. Energy released when one atom of uranium undergoes nuclear fission according to the following reaction is (atomic mass of U= 235.060; n= 1.009; Ba = 143.881 and Kr= 89.947) about 92​U235+0​n1→56​Ba144+36​Kr90+20​n1