Energy released on combustion of 7 g of ethene is kJ. (The combustion enthalpy of ethene (Δ H °)=.-1411 kJ mol -1)

Question

Energy released on combustion of 7 g of ethene is kJ. (The combustion enthalpy of ethene (Δ H °)=.-1411 kJ mol -1) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

C 2 H 4+3 O 2 longrightarrow 2 CO 2+2 H 2 O Moles C 2 H 4=(7/28)=0.25 mole Energy released on combustion of 1 mole of ethene =1411 kJ Hence, energy released on combustion of 0.25 mol ethene =0.25 ×(1411) =352.75 kJ

Q. Energy released on combustion of $7 g$ of ethene is ____ $k J$ .
(The combustion enthalpy of ethene $(Δ H^{\circ}) = - 1411 k J m o l^{- 1})$

$C_{2} H_{4} + 3 O_{2} ⟶ 2 C O_{2} + 2 H_{2} O$
Moles $C_{2} H_{4} = \frac{7}{28} = 0.25$ mole
Energy released on combustion of $1$ mole of ethene $= 1411 k J$
Hence, energy released on combustion of $0.25 m o l$ ethene $= 0.25 \times (1411)$
$= 352.75 k J$

Q. Energy released on combustion of 7g of ethene is ____kJ. (The combustion enthalpy of ethene (ΔH∘)=−1411kJmol−1)

C2​H4​+3O2​⟶2CO2​+2H2​O Moles C2​H4​=287​=0.25 mole Energy released on combustion of 1 mole of ethene =1411kJ Hence, energy released on combustion of 0.25mol ethene =0.25×(1411) =352.75kJ

Q. Energy released on combustion of $7 g$ of ethene is ____ $k J$ .
(The combustion enthalpy of ethene $(Δ H^{\circ}) = - 1411 k J m o l^{- 1})$

$C_{2} H_{4} + 3 O_{2} ⟶ 2 C O_{2} + 2 H_{2} O$
Moles $C_{2} H_{4} = \frac{7}{28} = 0.25$ mole
Energy released on combustion of $1$ mole of ethene $= 1411 k J$
Hence, energy released on combustion of $0.25 m o l$ ethene $= 0.25 \times (1411)$
$= 352.75 k J$