Energy of an atom is least when electron revolves in an orbit which is

Question

Energy of an atom is least when electron revolves in an orbit which is (A) closest to its nucleus (B) farthest from its nucleus (C) is of elliptical shape (D) is circular in shape

Tardigrade Admin · Accepted Answer

The energy of an atom is the least (largest negative value) when its electron is revolving in an orbit closest to the nucleus i.e., the one for which n=1. For n=2,3 ⋅s the absolute value of the energy E is smaller.

Q. Energy of an atom is least when electron revolves in an orbit which is

closest to its nucleus

farthest from its nucleus

is of elliptical shape

is circular in shape

The energy of an atom is the least (largest negative value) when its electron is revolving in an orbit closest to the nucleus i.e., the one for which $n = 1$ . For $n = 2, 3 \dots$ the absolute value of the energy $E$ is smaller.

Q. Energy of an atom is least when electron revolves in an orbit which is

closest to its nucleus

farthest from its nucleus

is of elliptical shape

is circular in shape

The energy of an atom is the least (largest negative value) when its electron is revolving in an orbit closest to the nucleus i.e., the one for which n=1. For n=2,3⋯ the absolute value of the energy E is smaller.

The energy of an atom is the least (largest negative value) when its electron is revolving in an orbit closest to the nucleus i.e., the one for which $n = 1$ . For $n = 2, 3 \dots$ the absolute value of the energy $E$ is smaller.