Empirical formula of a compound is CH2O and its vapour density is 30. Molecular formula of the compound is

Question

Empirical formula of a compound is CH2O and its vapour density is 30. Molecular formula of the compound is (A) C2H6O3 (B) C2H4O2 (C) C2H4O (D) CH2O

Tardigrade Admin · Accepted Answer

Empirical formula = CH2O Empirical formula mass =12 + 2+16 = 30 Mol. mass =2 × V.D. =2 × 30=60 n=( textMol. mass/ textEmpencal mass) =(60/32)=2 Molecular formula = text (emperical formula)n =(CH2O)2 =C2H4O2

Q. Empirical formula of a compound is $C H_{2} O$ and its vapour density is 30. Molecular formula of the compound is

$C_{2} H_{6} O_{3}$

$C_{2} H_{4} O_{2}$

$C_{2} H_{4} O$

$C H_{2} O$

Empirical formula $= C H_{2} O$
Empirical formula mass $= 12 + 2 + 16 = 30$
Mol. mass $= 2 \times V . D . = 2 \times 30 = 60$
$n = \frac{Mol. mass}{Empencal mass}$
$= \frac{60}{32} = 2$
Molecular formula $= (emperical formula)_{n}$
$= (C H_{2} O)_{2} = C_{2} H_{4} O_{2}$

Q. Empirical formula of a compound is CH2​O and its vapour density is 30. Molecular formula of the compound is

C2​H6​O3​

C2​H4​O2​

C2​H4​O

CH2​O