Electrolyte KCl KNO3 HCl NaOAc NaCl Lambda∞ (S cm2 mol-1) 149.9 145.0 426.2 91.0 126.5 Calculate Lambda∞HoAc using appropriate molar conductances of the electrolytes listed above at infinite dilution in H2O at 25° C :

Question

Electrolyte KCl KNO3 HCl NaOAc NaCl Lambda∞ (S cm2 mol-1) 149.9 145.0 426.2 91.0 126.5 Calculate Lambda∞HoAc using appropriate molar conductances of the electrolytes listed above at infinite dilution in H2O at 25° C : (A) 217.5 (B) 390.7 (C) 552.7 (D) 517.2

Tardigrade Admin · Accepted Answer

Lambda∞AcOH = Lambda ∞ AcON + Lambda ∞ HCl - Lambda ∞ NaCl = 91.0+ 426.2- 126.5 = 390.7

Q.

Electrolyte $K Cl$ $K N O_{3}$ $H Cl$ $N a O A c$ $N a Cl$

$Λ^{\infty} (S c m^{2} m o l^{- 1})$ $149.9$ $145.0$ $426.2$ $91.0$ $126.5$

Calculate $Λ^{\infty} Ho A c$ using appropriate molar conductances of the electrolytes listed above at infinite dilution in $H_{2} O$ at $2 5^{\circ}$ C :

217.5

390.7

552.7

517.2

$Λ_{A c O H}^{\infty} = Λ_{A c ON}^{\infty} + Λ_{H Cl}^{\infty} - Λ_{N a Cl}^{\infty}$
$= 91.0 + 426.2 - 126.5$
$= 390.7$

Q. Electrolyte KCl KNO3​ HCl NaOAc NaCl Λ∞(Scm2mol−1) 149.9 145.0 426.2 91.0 126.5 Calculate Λ∞HoAc using appropriate molar conductances of the electrolytes listed above at infinite dilution in H2​O at 25∘ C :