Q. Each resistance in the given cubical network has resistance of $1 Ω$ and equivalent resistance between $A$ and $B$ is

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A

$\frac{5}{6} Ω$

42%

B

$\frac{6}{5} Ω$

18%

C

$\frac{5}{12} Ω$

31%

D

$\frac{12}{5} Ω$

9%

Solution:

$5/6 Ω$