E° values for the half cell reactions are given below: Cu2++e- → Cu+ ; E°=0.15 V Cu2++2e- → Cu ; E°=0.34 V What will be the E° of the half-cell: Cu+ +e- → Cu ?

Question

E° values for the half cell reactions are given below: Cu2++e- → Cu+ ; E°=0.15 V Cu2++2e- → Cu ; E°=0.34 V What will be the E° of the half-cell: Cu+ +e- → Cu ? (A) +0.49 V (B) +0.19 V (C) +0.53 V (D) +0.30 V

Tardigrade Admin · Accepted Answer

Cu2++e- → Cu+ ; Cu2++2e- → Cu ; Cu++e- → Cu ; E°1=0.15 V, Δ G°1, n1=1 E°2=0.34 V, Δ G°2, n2=2 E°3=?, Δ G°3, n3=1 Δ G°3=Δ G°2-Δ G°1 ⇒ -n3FE°3=-n2FE°2+n1FE°1 -E°3=-2×0.34+1×0.15 E°3=0.68-0.15=+0.53 V

Q. $E^{\circ}$ values for the half cell reactions are given below :
$C u^{2 +} + e^{-} \to C u^{+}$ ; $E^{\circ} = 0.15 V$
$C u^{2 +} + 2 e^{-} \to C u$ ; $E^{\circ} = 0.34 V$
What will be the $E^{\circ}$ of the half-cell : $C u^{+} + e^{-} \to C u$ ?

$+ 0.49 V$

$+ 0.19 V$

$+ 0.53 V$

$+ 0.30 V$

Q. E∘ values for the half cell reactions are given below : Cu2++e−→Cu+ ; E∘=0.15V Cu2++2e−→Cu ; E∘=0.34V What will be the E∘ of the half-cell : Cu++e−→Cu ?

+0.49V

+0.19V

+0.53V

+0.30V

Cu2++e−→Cu+ ; Cu2++2e−→Cu ; Cu++e−→Cu ; E1∘​=0.15V,ΔG1∘​,n1​=1 E2∘​=0.34V,ΔG2∘​,n2​=2 E3∘​=?, ΔG3∘​, n3​=1 ΔG3∘​=ΔG2∘​−ΔG1∘​ ⇒−n3​FE3∘​=−n2​FE2∘​+n1​FE1∘​ −E3∘​=−2×0.34+1×0.15 E3∘​=0.68−0.15=+0.53V

Q. $E^{\circ}$ values for the half cell reactions are given below :
$C u^{2 +} + e^{-} \to C u^{+}$ ; $E^{\circ} = 0.15 V$
$C u^{2 +} + 2 e^{-} \to C u$ ; $E^{\circ} = 0.34 V$
What will be the $E^{\circ}$ of the half-cell : $C u^{+} + e^{-} \to C u$ ?

$+ 0.49 V$

$+ 0.19 V$

$+ 0.53 V$

$+ 0.30 V$