Question

$E^{\circ }=\frac{RT}{nF}\ln K_{eq}$, this equation is called

• A. Gibb's equation
• B. Gibbs's-Helmholtz equation
• C. Nernst equation
• D. van der Waals' equation

Answer 1

Answer: (C)

To determine the electrode potential (E) produced, Nemst gave the following equal:
$E=E^{\circ }-\frac{RT}{nF}{\log }_{n}K$
$E=E^{\circ }$
$E^{\circ }=\frac{RT}{nF}{\log }_{n}K$
or $E^{\circ }=\frac{2.303RT}{nF}{\log }_{10}\left[M^{n+}\right]$
$E=$ electrode potential developed
$E^{\circ }=$ standard reduction potential
$R=$ gas constant $(8.3J/K/mol)$
$T=$ temperature,
$F=$ Faraday constant
$n=$ number of electron taking pans in reduction and oxidation