Question

$E_{M{n}^{3+}/M{n}^{2+}}^{\circ }$ is highly positive than that of $E_{C{r}^{3+}/C{r}^{2+}}^{\circ }$ or $E_{F{e}^{3+}/F{e}^{2+}}^{\circ }$ because

• A. $M{n}^{2+}(d^5)$ can be easily oxidised to $M{n}^{3+}(d^4)$ due to low ionisation enthalpy
• B. third ionisation enthalpy of $Mn$ is much larger due to stable half filled $d^5$ electronic configuration of $M{n}^{2+}$
• C. $M{n}^{3+}$ is more stable than $M{n}^{2+}$ due to higher oxidation state
• D. second ionisation enthalpy of Mn is higher than third ionisation enthalpy

Answer 1

Answer: (B)

Correct answer is (b) third ionisation enthalpy of $Mn$ is much larger due to stable half filled $d^5$ electronic configuration of $M{n}^{2+}$