Q. E° for the cell, Z n|Z n2+(a q) | C u2+(a q)| C u is 1.10 V at 25° C. The equilibrium constant for the reaction, Z n(s)+C u2+(a q) leftharpoons C u(s)+Z n2+(a q) is of the order

Question

Q. E° for the cell, Z n|Z n2+(a q) | C u2+(a q)| C u is 1.10 V at 25° C. The equilibrium constant for the reaction, Z n(s)+C u2+(a q) leftharpoons C u(s)+Z n2+(a q) is of the order (A) 10-37 (B) 1037 (C) 10-17 (D) 1017

Tardigrade Admin · Accepted Answer

Z n(s)+C u2+(a q) leftharpoons C u(s)+Z n2+(a q) E0=+1.10 V ∴ E0=(0.0591/n) log 10 Ke q because at equilibrium, E text cell =0 (n = number of electrons exchanged =2 ) 1.10=(0.0591/2) log 10 Ke q (2.20/0.0591)= log 10 Ke q Ke q= antilog 37.225 Ke q=1.66 × 10-37

Q. Q. $E^{\circ}$ for the cell, $Z n ∣ ∣ Z n^{2 +} (a q) ∥ C u^{2 +} (a q) ∣ ∣ C u$ is $1.10 V$ at $2 5^{\circ} C$ . The equilibrium constant for the reaction, $Z n (s) + C u^{2 +} (a q) ⇌ C u (s) + Z n^{2 +} (a q)$ is of the order

$1 0^{- 37}$

$1 0^{37}$

$1 0^{- 17}$

$1 0^{17}$

Q. Q. E∘ for the cell, Zn∣∣​Zn2+(aq)∥Cu2+(aq)∣∣​Cu is 1.10V at 25∘C. The equilibrium constant for the reaction, Zn(s)+Cu2+(aq)⇌Cu(s)+Zn2+(aq) is of the order

10−37

1037

10−17

1017

Zn(s)+Cu2+(aq)⇌Cu(s)+Zn2+(aq) E0=+1.10V ∴E0=n0.0591​log10​Keq​ because at equilibrium, Ecell ​=0 (n= number of electrons exchanged =2 ) 1.10=20.0591​log10​Keq​ 0.05912.20​=log10​Keq​ Keq​= antilog 37.225 Keq​=1.66×10−37

Q. Q. $E^{\circ}$ for the cell, $Z n ∣ ∣ Z n^{2 +} (a q) ∥ C u^{2 +} (a q) ∣ ∣ C u$ is $1.10 V$ at $2 5^{\circ} C$ . The equilibrium constant for the reaction, $Z n (s) + C u^{2 +} (a q) ⇌ C u (s) + Z n^{2 +} (a q)$ is of the order

$1 0^{- 37}$

$1 0^{37}$

$1 0^{- 17}$

$1 0^{17}$