During the charging of a lead-acid storage battery, the cathode reaction is

Question

During the charging of a lead-acid storage battery, the cathode reaction is (A) formation of textPbS textO4  (B) reduction of textP textb text2+ to Pb (C) formation of textPb textO text2  (D) oxidation of Pb to textP textb text2+

Tardigrade Admin · Accepted Answer

During the charging of a lead acid storage battery, electrode reactions are as follows: Cathode anode: Pb2+2e- xrightarrowPb At cathode: PbSO4+2H2O xrightarrowPbO2 xrightarrowSO42-+2e- or Pb2+ xrightarrowPb4++2e-

Q. During the charging of a lead-acid storage battery, the cathode reaction is

formation of $PbS O_{4}$

reduction of $P b^{2+}$ to Pb

formation of $Pb O_{2}$

oxidation of Pb to $P b^{2+}$

During the charging of a lead acid storage battery, electrode reactions are as follows : Cathode anode: $P b^{2} + 2 e^{-} P b$ At cathode: $P b S O_{4} + 2 H_{2} O P b O_{2} S O_{4}^{2 -} + 2 e^{-}$ or $P b^{2 +} P b^{4 +} + 2 e^{-}$

Q. During the charging of a lead-acid storage battery, the cathode reaction is

formation of PbSO4​

reduction of Pb2+ to Pb

formation of PbO2​

oxidation of Pb to Pb2+

During the charging of a lead acid storage battery, electrode reactions are as follows : Cathode anode: Pb2+2e−​Pb At cathode: PbSO4​+2H2​O​PbO2​​SO42−​+2e− or Pb2+​Pb4++2e−

formation of $PbS O_{4}$

reduction of $P b^{2+}$ to Pb

formation of $Pb O_{2}$

oxidation of Pb to $P b^{2+}$

During the charging of a lead acid storage battery, electrode reactions are as follows : Cathode anode: $P b^{2} + 2 e^{-} P b$ At cathode: $P b S O_{4} + 2 H_{2} O P b O_{2} S O_{4}^{2 -} + 2 e^{-}$ or $P b^{2 +} P b^{4 +} + 2 e^{-}$