Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
During reduction of carbonyl compounds by H2NNH2 and KOH, the first intermediate is:
Q. During reduction of carbonyl compounds by
H
2
NN
H
2
and
K
O
H
, the first intermediate is:
2318
264
Aldehydes Ketones and Carboxylic Acids
Report Error
A
RC
=
N
9%
B
RCON
H
2
32%
C
RC
H
=
N
H
20%
D
RC
H
=
NN
H
2
39%
Solution:
