During compression of a spring the work done is 10 kJ and 2 kJ escaped to the surroundings as heat. The change in internal energy, Δ U(in kJ) is:

Question

During compression of a spring the work done is 10 kJ and 2 kJ escaped to the surroundings as heat. The change in internal energy, Δ U(in kJ) is: (A) 8 (B) 12 (C) - 12 (D) -8

Tardigrade Admin · Accepted Answer

Δ U = q + w q = - 2 kJ, W = 10 kJ Δ U = 8 kJ

Q. During compression of a spring the work done is $10 k J$ and $2 k J$ escaped to the surroundings as heat. The change in internal energy, $Δ U (in k J)$ is:

8

12

- 12

-8

$Δ U = q + w$
$q = - 2 k J, W = 10 k J$
$Δ U = 8 k J$

Q. During compression of a spring the work done is 10kJ and 2kJ escaped to the surroundings as heat. The change in internal energy, ΔU(inkJ) is:

8

12

- 12

-8

ΔU=q+w q=−2kJ,W=10kJ ΔU=8kJ

Q. During compression of a spring the work done is $10 k J$ and $2 k J$ escaped to the surroundings as heat. The change in internal energy, $Δ U (in k J)$ is:

$Δ U = q + w$
$q = - 2 k J, W = 10 k J$
$Δ U = 8 k J$