Dissolving NaCN in de-ionized water will result in a solution having

Question

Dissolving NaCN in de-ionized water will result in a solution having (A) pH < 7 (B) pH = 7 (C) pOH = 7 (D) pH > 7

Tardigrade Admin · Accepted Answer

∵ On dissolving NaCN in de-ionised water, following reaction takes place. CN -+ H 2 O leftharpoons HCN + OH - ∵ CN -ions come from the salt of strong base and weak acid. ∴ The solution becomes basic and pH >7.

Q. Dissolving $N a CN$ in de-ionized water will result in a solution having

pH < 7

pH = 7

pOH = 7

pH > 7

$∵$ On dissolving NaCN in de-ionised water, following reaction takes place.
$C N^{-} + H_{2} O ⇌ H CN + O H^{-}$
$∵ C N^{-}$ ions come from the salt of strong base and weak acid.
$∴$ The solution becomes basic and $p H > 7$ .

Q. Dissolving NaCN in de-ionized water will result in a solution having