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Tardigrade
Question
Physics
Dimensions of Stefan's constant is
Q. Dimensions of Stefan's constant is
95
148
Manipal
Manipal 2020
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A
[
M
L
T
−
3
θ
−
4
]
B
[
M
T
−
3
θ
−
4
]
C
[
M
2
T
−
3
θ
−
4
]
D
[
M
2
T
−
2
θ
−
4
]
Solution:
Stefan's constant,
σ
=
T
4
E
(where,
E
is energy/s area)
=
[
T
]
[
L
2
]
[
θ
4
]
[
M
L
2
T
−
2
]
=
[
M
T
−
3
θ
−
4
]